AP Calculus AB Practice Quiz: Connecting a Function, Its First Derivative, and Its Second Derivative
Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026
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Question 1 of 7
All Questions (7)
A) f(x) is increasing.
B) f(x) is decreasing.
C) f(x) is concave up.
D) f(x) is concave down.
Correct Answer: B
The sign of the first derivative, f'(x), determines whether the function f(x) is increasing or decreasing. A negative first derivative (f'(x) < 0) on an interval indicates that the function f(x) is decreasing on that interval.
A) The graph of f'(x) is decreasing.
B) The graph of f'(x) is below the x-axis.
C) The graph of f'(x) is increasing.
D) The graph of f'(x) is above the x-axis.
Correct Answer: C
The second derivative, f''(x), is the derivative of the first derivative, f'(x). Just as a positive first derivative indicates that the original function is increasing, a positive second derivative indicates that the first derivative function, f'(x), is increasing.
A) f(x) has a local minimum at x = 2.
B) f(x) has a point of inflection at x = 2.
C) f(x) has a local maximum at x = 2.
D) The behavior of f(x) cannot be determined at x = 2.
Correct Answer: C
This is an application of the Second Derivative Test. When the first derivative is zero at a point (indicating a horizontal tangent), the sign of the second derivative determines the nature of the extremum. Since f'(2) = 0 and f''(2) < 0 (indicating the function is concave down), f(x) has a local maximum at x = 2.
A) Increasing and concave up
B) Decreasing and concave up
C) Increasing and concave down
D) Decreasing and concave down
Correct Answer: B
The sign of the first derivative determines if the function is increasing or decreasing. Since f'(x) < 0, the function f(x) is decreasing. The sign of the second derivative determines the concavity. Since f''(x) > 0, the function f(x) is concave up. Therefore, the function is decreasing and concave up.
A) f(x) has a local maximum.
B) f(x) has a local minimum.
C) f(x) has a point of inflection.
D) f(x) has a zero.
Correct Answer: C
A point of inflection on the graph of f(x) occurs where the concavity changes. The concavity of f(x) is determined by the sign of f''(x). The sign of f''(x) determines whether f'(x) is increasing or decreasing. If f'(x) changes from decreasing to increasing, it means f''(x) changes from negative to positive. This change in the sign of the second derivative corresponds to a point of inflection on the graph of f(x).
A) A local maximum
B) A point of inflection
C) A zero
D) A local minimum
Correct Answer: C
If f'(x) has a local maximum at x = a, its derivative must be zero at that point (assuming the derivative exists). The derivative of f'(x) is f''(x). Therefore, f''(a) must be equal to 0. This corresponds to a zero (an x-intercept) on the graph of f''(x).
A) f'(5) = 0 and f''(5) > 0
B) f'(x) is constant around x = 5.
C) f''(x) has a local extremum at x = 5.
D) f'(x) has a local extremum at x = 5.
Correct Answer: D
A point of inflection on f(x) occurs where the concavity changes, which means f''(x) changes sign. For f''(x) to change sign at x = 5, it must be that f''(5) = 0 or is undefined. If f''(5) = 0, this means that the derivative of f'(x) is zero at x = 5, which is the condition for f'(x) to have a critical point. This critical point is often a local extremum (maximum or minimum) on the graph of f'(x).