AP Calculus BC Practice Quiz: Defining the Derivative of a Function and Using Derivative Notation
Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026
Test your understanding with short quizzes. This quiz has 15 questions to check your progress.
Question 1 of 15
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A) lim_{h -> 0} (f(x+h) - f(x))
B) lim_{h -> 0} (f(x+h) - f(x)) / h
C) lim_{h -> 0} (f(x) - f(h)) / h
D) (f(b) - f(a)) / (b - a)
Correct Answer: B
The formal definition of the derivative of a function f is the limit of the difference quotient, which is given by the expression lim_{h -> 0} (f(x+h) - f(x)) / h. Option D represents the average rate of change, not the instantaneous rate of change.
A) f'(x)
B) y'
C) dy/dx
D) f(x')
Correct Answer: D
The standard notations for the derivative of y = f(x) include f'(x) (prime notation), y' (prime notation), and dy/dx (Leibniz notation). The notation f(x') is not a standard representation for the derivative.
A) average rate of change of the function over an interval.
B) y-value of the function at that point.
C) slope of the line tangent to the function's graph at that point.
D) area under the curve at that point.
Correct Answer: C
By definition, the derivative of a function at a point is the slope of the line tangent to the graph of the function at that point. It represents the instantaneous rate of change.
A) lim_{h -> 0} (5(x+h)^2 - 5x^2) / h
B) lim_{h -> 0} (5x^2 + h - 5x^2) / h
C) lim_{h -> 0} (5(x^2+h) - 5x^2) / h
D) (5(x+h)^2 - 5x^2) / h
Correct Answer: A
The derivative is defined as lim_{h -> 0} (f(x+h) - f(x)) / h. For f(x) = 5x^2, we have f(x+h) = 5(x+h)^2. Substituting these into the definition gives the expression in option A.
A) f(x) = sin(x) at x = π/2
B) f(x) = cos(x) at x = 0
C) f(x) = cos(x) at x = π/2
D) f(x) = sin(x) at x = 0
Correct Answer: C
The given limit matches the form lim_{h -> 0} (f(a+h) - f(a)) / h. In this case, the function is f(x) = cos(x) and the point is a = π/2. Therefore, the limit represents f'(π/2) for f(x) = cos(x).
A) 3
B) -4
C) 1/4
D) -1/3
Correct Answer: B
The derivative of a function at a point, f'(a), is defined as the slope of the line tangent to the function's graph at x = a. Therefore, the slope of the tangent line at x = 3 is f'(3), which is -4.
A) f(x) = ln(x)
B) f(x) = ln(3x)
C) f(x) = 3ln(x)
D) f(x) = ln(3)
Correct Answer: B
The expression matches the definition of the derivative, lim_{h -> 0} (f(x+h) - f(x)) / h, for the function f(x) = ln(3x), because f(x+h) would be ln(3(x+h)).
A) Graphical
B) Numerical
C) Analytical
D) Verbal
Correct Answer: B
Using a table of values to approximate the derivative is a numerical representation. An analytical representation would be a formula, a graphical one would be a graph of the derivative, and a verbal one would be a description in words.
A) y = -2x + 8
B) y = -2x + 10
C) y = 8x - 2
D) y - 1 = -2(x - 8)
Correct Answer: B
Using the point-slope form of a line, y - y1 = m(x - x1), with the point (1, 8) and slope m = -2, we get y - 8 = -2(x - 1). Simplifying gives y - 8 = -2x + 2, which leads to y = -2x + 10.
A) The function f(x) itself.
B) The derivative of the function, f'(x).
C) The average slope of the function.
D) The y-intercept of the tangent line.
Correct Answer: B
The limit of the difference quotient is the fundamental definition of the derivative of a function, f'(x), which represents the instantaneous rate of change of the function.
A) f(x) = sqrt(x) at a = 4
B) f(x) = sqrt(x) at a = 2
C) f(x) = x at a = 4
D) f(x) = x - 4 at a = 2
Correct Answer: A
This limit is in the form lim_{x -> a} (f(x) - f(a)) / (x - a). Here, f(x) = sqrt(x), a = 4, and f(a) = f(4) = sqrt(4) = 2. Thus, the limit represents f'(4) for f(x) = sqrt(x).
A) f'(x) = 5x
B) f'(x) = 0
C) f'(x) = 5
D) f'(x) is undefined.
Correct Answer: C
The derivative at a point is the slope of the tangent line at that point. For a straight line, the tangent line at any point is the line itself. Since the line has a constant slope of 5, its derivative must be the constant value 5 for all x.
A) g(-1) = 1/2
B) g'(x) = 1/2
C) g'(-1) = 1/2
D) dy/dx = -1
Correct Answer: C
The derivative of a function at a point, g'(a), gives the instantaneous rate of change at x = a. Therefore, the statement that the instantaneous rate of change at x = -1 is 1/2 is written as g'(-1) = 1/2.
A) lim_{h -> 0} (1/(x+h+3) - 1/(x+3)) / h
B) lim_{h -> 0} (1/(x+3) + h - 1/(x+3)) / h
C) lim_{h -> 0} ((1/x + h + 3) - (1/x + 3)) / h
D) (1/(x+h+3) - 1/(x+3)) / h
Correct Answer: A
Using the definition f'(x) = lim_{h -> 0} (f(x+h) - f(x)) / h, we substitute f(x) = 1/(x+3). This means f(x+h) = 1/((x+h)+3) = 1/(x+h+3). Plugging these into the formula gives the expression in option A. Option D is incorrect because it is missing the limit.
A) 9
B) 5
C) 4
D) Cannot be determined.
Correct Answer: B
The derivative of a function at a point, g'(-1), is the slope of the tangent line at that point. The equation of the tangent line is given in slope-intercept form, y = mx + b, where m is the slope. In this case, the slope is 5. Therefore, g'(-1) = 5.