AP Physics 1: Algebra-Based Practice Quiz: Scalars and Vectors in One Dimension
Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026
Test your understanding with short quizzes. This quiz has 16 questions to check your progress.
Question 1 of 16
All Questions (16)
A) A quantity described by both magnitude and direction.
B) A quantity described by magnitude only.
C) A quantity described by direction only.
D) A quantity that can only be positive.
Correct Answer: B
Based on the provided content, scalars are quantities described by magnitude (a numerical value) only. Vectors require both magnitude and direction.
A) The speed of a car, 25 m/s.
B) The distance a person walked, 500 meters.
C) The mass of a block, 10 kg.
D) The acceleration of a falling object, 9.8 m/s² downward.
Correct Answer: D
Acceleration is a vector quantity because it has both magnitude (9.8 m/s²) and direction (downward). Speed and distance are listed as examples of scalar quantities.
A) +15 m
B) -15 m
C) +5 m
D) -5 m
Correct Answer: B
Displacement is a vector quantity representing the change in position (final position - initial position). The calculation is a vector sum: (-5 m) - (+10 m) = -15 m. The negative sign indicates the displacement is in the negative direction (left).
A) As a point on a graph, where the coordinates give magnitude and direction.
B) As a number with a positive or negative sign.
C) As an arrow with a length proportional to its magnitude and pointing in its direction.
D) As a scalar value multiplied by a unit of time.
Correct Answer: C
The content states that vectors can be visually modeled as arrows. The length of the arrow is proportional to the vector's magnitude, and the way the arrow points indicates the vector's direction.
A) +13 m
B) -13 m
C) +3 m
D) -3 m
Correct Answer: C
In the given one-dimensional coordinate system, the eastward displacement is +8 m. The westward displacement is in the opposite direction, so it is denoted by a negative sign, -5 m. The vector sum is (+8 m) + (-5 m) = +3 m.
A) The object is slowing down.
B) The magnitude of the velocity is 15 m/s.
C) The direction of the velocity is opposite to the defined positive direction.
D) The object's acceleration is negative.
Correct Answer: C
The content specifies that in one dimension, the sign of a vector component completely describes its direction. A negative sign indicates that the vector points in the direction opposite to the one defined as positive for that coordinate system.
A) The distance is 400 m, and the displacement is 400 m.
B) The distance is 0 m, and the displacement is 400 m.
C) The distance is 400 m, and the displacement is 0 m.
D) The distance is 0 m, and the displacement is 0 m.
Correct Answer: C
Distance is a scalar representing the total path length, which is 400 m. Displacement is a vector representing the change in position from the start point to the end point. Since the athlete finished at the starting point, the net change in position is zero.
A) Distance and Speed
B) Position and Displacement
C) Speed and Velocity
D) Velocity and Acceleration
Correct Answer: C
According to the provided content, speed is a scalar quantity (magnitude only), while velocity is a vector quantity (magnitude and direction). The other pairs consist of two scalars (A) or two vectors (B, D).
A) +10 m/s
B) -10 m/s
C) 0 m/s
D) Cannot be determined
Correct Answer: B
The change in velocity is a vector sum: final velocity minus initial velocity. In this one-dimensional case, Change = (-10 m/s) - (0 m/s) = -10 m/s.
A) Velocity is positive, acceleration is positive.
B) Velocity is positive, acceleration is negative.
C) Velocity is negative, acceleration is positive.
D) Velocity is negative, acceleration is negative.
Correct Answer: B
The car is moving in the positive direction, so its velocity is positive. Because it is slowing down, its acceleration must be in the opposite direction to its velocity. Therefore, the acceleration is negative.
A) only magnitude.
B) only direction.
C) both magnitude and direction.
D) a standard unit in the SI system.
Correct Answer: C
This is the fundamental definition of a vector provided in the content. Vectors are quantities described by both magnitude and direction.
A) An arrow of length 2.5 cm pointing to the left.
B) An arrow of length 10 cm pointing to the right.
C) An arrow of length 5 cm pointing to the right.
D) An arrow of length 2.5 cm pointing to the right.
Correct Answer: D
The new vector has half the magnitude, so its arrow should be half the length (2.5 cm). It is in the opposite direction, so if the original pointed left, the new one must point right.
A) -3.0 m/s
B) -2.5 m/s
C) -1.0 m/s
D) +3.0 m/s
Correct Answer: A
The change in velocity is the product of the acceleration vector and the time scalar. The calculation is a one-dimensional vector operation: (-1.5 m/s²) * (2 s) = -3.0 m/s. The initial velocity is not needed to find the change in velocity.
A) Vector notation with arrows is always required.
B) The sign of the component (+ or -) is sufficient to describe the direction.
C) Only positive numbers can be used for vector components.
D) The magnitude of a vector is always larger than its component.
Correct Answer: B
The provided content explicitly states that in one dimension, the sign of the component completely describes the direction of that component, and formal vector notation is not required.
A) A vector sum resulting in a final position on the 2nd floor.
B) A vector sum resulting in a final position on the 3rd floor.
C) A scalar sum of 16 floors.
D) A vector sum of (+9 floors) + (-7 floors).
Correct Answer: D
Displacement is a vector. The first movement is from 1 to 10, which is a displacement of +9 floors. The second movement is from 10 to 3, which is a displacement of -7 floors. The total displacement is the vector sum of these two individual displacements.
A) +30 m/s
B) +10 m/s
C) -10 m/s
D) -30 m/s
Correct Answer: C
The change in velocity is a vector sum defined as final velocity minus initial velocity. Δv = v_final - v_initial = (+10 m/s) - (+20 m/s) = -10 m/s. The negative sign indicates the change was in the negative direction, causing the car to slow down.