AP Physics C: Electricity and Magnetism Practice Quiz: Electric Potential Energy
Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026
Test your understanding with short quizzes. This quiz has 9 questions to check your progress.
Question 1 of 9
All Questions (9)
A) U_E = k * (q1*q2) / r^2
B) U_E = k * (q1+q2) / r
C) U_E = k * (q1*q2) / r
D) U_E = k * q1 / r
Correct Answer: C
The provided content explicitly gives the equation for the electric potential energy between two charged objects as U_E = k * (q1*q2) / r.
A) It is doubled.
B) It is quadrupled.
C) It is halved.
D) It is quartered.
Correct Answer: C
The electric potential energy is given by U_E = k * (q1*q2) / r. Since the energy is inversely proportional to the distance 'r', doubling the distance (2r) will cause the potential energy to become half of its original value.
A) By calculating the energy of the strongest interaction only.
B) By summing the potential energies of the pairs (qA, qB), (qA, qC), and (qB, qC).
C) By averaging the potential energies of all three charges with respect to a reference point.
D) By multiplying the individual potential energies of the three pairs.
Correct Answer: B
The content states that the total electric potential energy is determined by finding the sum of the electric potential energies of the individual interactions between each pair of charged objects. For three charges, there are three unique pairs.
A) Positive
B) Negative
C) Zero
D) It cannot be determined without knowing the distance.
Correct Answer: B
Using the formula U_E = k * (q1*q2) / r, the product of the charges is (+q) * (-q) = -q^2. Since k, q^2, and r are all positive, the resulting potential energy will be negative.
A) The kinetic energy of the system.
B) A proportionality constant (1 / 4πε₀).
C) The distance between the charges.
D) The magnitude of the smaller charge.
Correct Answer: B
The provided content defines the electric potential energy equation as U_E = (1 / 4πε₀) * (q1*q2) / r = k * (q1*q2) / r, explicitly showing that 'k' is the constant 1 / 4πε₀.
A) 2 * U_E
B) 3 * U_E
C) 5 * U_E
D) 6 * U_E
Correct Answer: D
The original energy is U_E = k * (q1*q2) / r. The new charges are 2*q1 and 3*q2. The new energy is U_new = k * ((2*q1)*(3*q2)) / r = 6 * (k * (q1*q2) / r) = 6 * U_E.
A) The charges must be equal in magnitude.
B) The charges must be opposite in sign.
C) The distance 'r' approaches infinity.
D) The product of the charges (q1*q2) is positive.
Correct Answer: C
In the equation U_E = k * (q1*q2) / r, for U_E to be zero, either the numerator (q1*q2) must be zero or the denominator 'r' must approach infinity. The question assumes charges exist, so the standard reference point for zero potential energy is when the charges are infinitely far apart.
A) 3
B) 4
C) 6
D) 12
Correct Answer: C
For a system of four charges (1, 2, 3, 4), one must find the energy for each unique pair. The pairs are (1,2), (1,3), (1,4), (2,3), (2,4), and (3,4). This results in a total of 6 interactions to be summed.
A) U_E / 3
B) U_E / 9
C) 3 * U_E
D) 9 * U_E
Correct Answer: C
The initial energy is U_E = k * (q * 2q) / r. The new energy is U_new = k * (q * 2q) / (r/3). Dividing by r/3 is the same as multiplying by 3/r. Therefore, U_new = 3 * [k * (q * 2q) / r] = 3 * U_E.