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AP Physics C: Electricity and Magnetism Practice Quiz: Magnetism and Moving Charges

Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026

Test your understanding with short quizzes. This quiz has 14 questions to check your progress.

Question 1 of 14

According to the provided content, which of the following is the fundamental source of a magnetic field?

All Questions (14)

According to the provided content, which of the following is the fundamental source of a magnetic field?

A) A stationary electric charge

B) A moving electric charge

C) A constant electric field

D) A region of empty space

Correct Answer: B

The content explicitly states that 'A single moving charged object produces a magnetic field.' Stationary charges produce electric fields, but not magnetic fields.

A proton is moving with a constant velocity. Which of the following statements is true regarding the fields it produces?

A) It produces only an electric field.

B) It produces only a magnetic field.

C) It produces both an electric field and a magnetic field.

D) It produces neither an electric nor a magnetic field.

Correct Answer: C

A proton is a charged object. All charged objects produce an electric field. Because it is a *moving* charged object, it also produces a magnetic field, as stated in the content.

An electron moves with velocity $\vec{v}$ through a uniform magnetic field $\vec{B}$. Under which condition will the electron experience zero magnetic force?

A) When its velocity is perpendicular to the magnetic field.

B) When its velocity is parallel to the magnetic field.

C) When it moves in a circular path.

D) The electron will always experience a force in a magnetic field.

Correct Answer: B

The magnetic force is given by $\vec{F}_{B}=q(\vec{v}\times\vec{B})$. The magnitude of the cross product is $|q|vB\sin\theta$, where $\theta$ is the angle between the velocity and the magnetic field. If the velocity is parallel to the field, $\theta=0^{\circ}$ or $\theta=180^{\circ}$, and $\sin\theta=0$, resulting in zero force.

A positive charge q moves with velocity $\vec{v}$ in a region with a magnetic field $\vec{B}$. The direction of the magnetic force $\vec{F}_{B}$ on the charge is:

A) in the same direction as the velocity $\vec{v}$.

B) in the same direction as the magnetic field $\vec{B}$.

C) in the direction opposite to the velocity $\vec{v}$.

D) perpendicular to both the velocity $\vec{v}$ and the magnetic field $\vec{B}$.

Correct Answer: D

The magnetic force is defined by the cross product $\vec{F}_{B}=q(\vec{v}\times\vec{B})$. A key property of the cross product is that the resulting vector ($\vec{F}_{B}$) is always perpendicular to the plane formed by the two input vectors ($\vec{v}$ and $\vec{B}$).

A proton enters a uniform magnetic field directed into the page. The proton's initial velocity is directed to the right. What is the initial direction of the magnetic force on the proton?

A) Upwards

B) Downwards

C) Into the page

D) To the left

Correct Answer: A

Using the right-hand rule for the cross product $\vec{F}_{B}=q(\vec{v}\times\vec{B})$: point your fingers in the direction of velocity (right), curl them into the direction of the magnetic field (into the page). Your thumb points in the direction of the force, which is upwards.

A charged particle is moving in a region with both a uniform electric field and a uniform magnetic field. How is the total force on the particle determined?

A) Only the stronger of the two forces acts on the particle.

B) The forces are added as vectors.

C) The forces are multiplied together.

D) The net force is always zero.

Correct Answer: B

The content states that 'a moving charged object will experience independent forces from each field.' This implies the principle of superposition, where the total force is the vector sum of the individual electric and magnetic forces.

A particle with charge +q moves at speed v perpendicular to a uniform magnetic field B, experiencing a force F. If the speed of the particle is doubled to 2v, what is the new magnetic force?

A) F/2

B) F

C) 2F

D) 4F

Correct Answer: C

The magnitude of the magnetic force is given by $F_B = |q|vB\sin\theta$. Since the force is directly proportional to the velocity v, doubling the velocity while keeping q, B, and the angle constant will double the force.

An electron and a proton enter a uniform magnetic field with the same velocity, which is perpendicular to the field. How do the magnetic forces they experience compare?

A) The forces have the same magnitude and same direction.

B) The forces have the same magnitude but opposite directions.

C) The force on the proton is greater in magnitude.

D) The force on the electron is greater in magnitude.

Correct Answer: B

The magnitude of the force is $F_B = |q|vB\sin\theta$. Since an electron and a proton have charges of the same magnitude (|e|), and v, B, and $\theta$ are the same, the magnitude of the force is identical. However, because their charges have opposite signs (q is negative for the electron and positive for the proton), the direction of the force vector $\vec{F}_{B}=q(\vec{v}\times\vec{B})$ will be opposite for each.

Under which of the following conditions will a magnetic field exert the maximum possible force on a moving charged object?

A) When the object's velocity is parallel to the magnetic field.

B) When the object's velocity is at a 45-degree angle to the magnetic field.

C) When the object's velocity is perpendicular to the magnetic field.

D) When the object is stationary.

Correct Answer: C

The magnitude of the magnetic force is $F_B = |q|vB\sin\theta$. The sine function has a maximum value of 1 when the angle $\theta$ is 90 degrees. Therefore, the force is maximum when the velocity is perpendicular to the magnetic field.

A charged particle moves through a region of space containing both an electric field $\vec{E}$ and a magnetic field $\vec{B}$. The particle's velocity is constant. Which statement must be true?

A) The electric and magnetic fields must both be zero.

B) The electric and magnetic forces on the particle must be perpendicular to each other.

C) The electric and magnetic forces on the particle must be equal in magnitude and opposite in direction.

D) The particle must be uncharged.

Correct Answer: C

If the velocity is constant, the acceleration is zero. By Newton's second law, the net force on the particle must be zero. The total force is the vector sum of the electric force ($\vec{F}_E$) and the magnetic force ($\vec{F}_B$). For the sum to be zero, the two forces must be equal in magnitude and point in opposite directions, such that $\vec{F}_E + \vec{F}_B = 0$.

A stationary proton is placed in a strong, uniform magnetic field. What is the magnetic force on the proton?

A) Zero

B) In the direction of the magnetic field

C) Opposite the direction of the magnetic field

D) Perpendicular to the magnetic field

Correct Answer: A

The magnetic force equation is $\vec{F}_{B}=q(\vec{v}\times\vec{B})$. If the object is stationary, its velocity $\vec{v}$ is zero. Therefore, the magnetic force is also zero. A magnetic field only exerts a force on *moving* charged objects.

A particle with charge q moves with velocity $\vec{v}$ through a magnetic field $\vec{B}$ and experiences a force $\vec{F}_{B}$. If the charge is changed to -2q while $\vec{v}$ and $\vec{B}$ remain the same, what is the new force?

A) $\vec{F}_{B}$

B) $2\vec{F}_{B}$

C) $-2\vec{F}_{B}$

D) $-1/2 \vec{F}_{B}$

Correct Answer: C

The force is directly proportional to the charge q, as seen in $\vec{F}_{B}=q(\vec{v}\times\vec{B})$. Changing the charge from q to -2q will multiply the force vector by -2. This doubles the magnitude and reverses the direction of the force.

A proton moves with velocity $\vec{v}$ parallel to a uniform electric field $\vec{E}$ and a uniform magnetic field $\vec{B}$, which are also parallel to each other. What is the net force on the proton?

A) Only a magnetic force

B) Only an electric force

C) The vector sum of an electric and a magnetic force

D) Zero net force

Correct Answer: B

The total force is the sum of the electric and magnetic forces. The electric force is $\vec{F}_E = q\vec{E}$. Since the proton is charged, there is an electric force. The magnetic force is $\vec{F}_{B}=q(\vec{v}\times\vec{B})$. Because the velocity $\vec{v}$ is parallel to the magnetic field $\vec{B}$, their cross product is zero. Therefore, the magnetic force is zero, and only the electric force acts on the proton.

Which of the following best describes the relationship between a moving charged object and a magnetic field?

A) A moving charge creates a magnetic field, but is not affected by external magnetic fields.

B) A moving charge is affected by external magnetic fields, but does not create its own.

C) A moving charge both creates a magnetic field and is affected by external magnetic fields.

D) A moving charge has no interaction with magnetic fields.

Correct Answer: C

The provided content covers both aspects: 'A single moving charged object produces a magnetic field' and 'A magnetic field will exert a force on a charged object moving within that field'. Therefore, a moving charge is both a source of and is influenced by magnetic fields.