AP Physics C: Electricity and Magnetism Practice Quiz: Circuits with Capacitors and Inductors (LC Circuits)
Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026
Test your understanding with short quizzes. This quiz has 10 questions to check your progress.
Question 1 of 10
All Questions (10)
A) Ohm's Law
B) Conservation of Energy
C) Kirchhoff's Junction Rule
D) Gauss's Law
Correct Answer: B
According to the provided content, in LC circuits, the maximum current in the inductor can be determined using conservation of energy. The initial potential energy stored in the capacitor's electric field (when current is zero) is converted into magnetic potential energy in the inductor (when charge is zero and current is maximum).
A) 4ω
B) 2ω
C) ω/2
D) ω/4
Correct Answer: C
The angular frequency of an LC circuit is given by the equation ω = 1/√(LC). If the capacitance C is replaced by 4C, the new angular frequency ω' will be ω' = 1/√(L(4C)) = 1/(2√(LC)) = ω/2.
A) Exponential decay
B) Uniform linear motion
C) Simple harmonic motion
D) Damped oscillation
Correct Answer: C
The provided content explicitly states that the time dependence of the charge stored in the capacitor can be modeled as simple harmonic motion, and it provides the corresponding differential equation. The form d²x/dt² = - (constant) * x is the mathematical definition of simple harmonic motion.
A) The maximum possible charge, Q_max
B) Half the maximum charge, Q_max/2
C) Zero
D) An indeterminate value between zero and Q_max
Correct Answer: C
Based on the principle of conservation of energy, the total energy in the circuit is constant. When the current is maximum, the energy stored in the inductor's magnetic field is maximum. For the total energy to remain constant, the energy stored in the capacitor's electric field must be zero. Since capacitor energy is U_C = q²/(2C), the charge q must be zero.
A) Double the inductance and double the capacitance.
B) Halve the inductance and halve the capacitance.
C) Double the inductance and halve the capacitance.
D) Quadruple the inductance and keep the capacitance the same.
Correct Answer: B
The angular frequency is ω = 1/√(LC). The new frequency is ω' = 2ω. We need to find L' and C' such that 1/√(L'C') = 2 * (1/√(LC)). Let's test the options. For option B, L' = L/2 and C' = C/2. Then ω' = 1/√((L/2)(C/2)) = 1/√(LC/4) = 2/√(LC) = 2ω. This is the correct modification.
A) A resistor and a capacitor
B) A battery and an inductor
C) A capacitor and an inductor
D) A resistor and a battery
Correct Answer: C
The provided content describes the physical and electrical properties of a circuit containing a combination of capacitors and a single inductor. This combination, an LC circuit, is the one in which charge exhibits simple harmonic motion.
A) The period of oscillation squared, T²
B) The angular frequency, ω
C) The square of the angular frequency, ω²
D) The maximum charge, Q_max
Correct Answer: C
By direct comparison of the two equations, the charge q is analogous to the position x. The term multiplying the negative q must be analogous to the term multiplying the negative x. Therefore, 1/LC is equivalent to ω², the square of the angular frequency. This leads directly to the derived equation ω = 1/√(LC).
A) Entirely in the magnetic field of the inductor.
B) Entirely in the electric field of the capacitor.
C) Equally shared between the inductor and the capacitor.
D) The circuit contains no energy at this instant.
Correct Answer: B
When the capacitor has maximum charge (q = Q_max), the rate of change of charge (current, i = dq/dt) is momentarily zero. According to the principle of energy conservation, the total energy is the sum of the capacitor's energy (q²/(2C)) and the inductor's energy (Li²/2). With i=0, all the energy is stored in the capacitor.
A) The period is directly proportional to both L and C.
B) The period is inversely proportional to the square root of the product of L and C.
C) The period is directly proportional to the square root of the product of L and C.
D) The period is independent of L and C.
Correct Answer: C
The period T is related to the angular frequency ω by T = 2π/ω. Substituting the expression for ω from the provided content, we get T = 2π / (1/√(LC)) = 2π√(LC). Therefore, the period is directly proportional to the square root of the product of L and C.
A) I_max = Q_max / (LC)
B) I_max = Q_max * √(L/C)
C) I_max = Q_max * √(C/L)
D) I_max = Q_max / √(LC)
Correct Answer: D
By conservation of energy, the maximum energy stored in the capacitor must equal the maximum energy stored in the inductor. So, U_C_max = U_L_max, which is (Q_max)²/(2C) = L(I_max)²/2. Solving for I_max: (Q_max)²/C = L(I_max)², so (I_max)² = (Q_max)²/(LC). Taking the square root gives I_max = Q_max / √(LC).