AP Physics C: Mechanics Practice Quiz: Change in Momentum and Impulse
Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026
Test your understanding with short quizzes. This quiz has 14 questions to check your progress.
Question 1 of 14
All Questions (14)
A) The object's change in kinetic energy.
B) The integral of the net force exerted on the object over a time interval.
C) The rate of change of the object's momentum.
D) The product of the object's mass and its final velocity.
Correct Answer: B
According to the provided content, impulse is defined as the integral of a force exerted on an object or system over a time interval. The relevant equation is J = ∫F_net(t)dt.
A) Net force and change in momentum.
B) Impulse and change in momentum.
C) Net force and impulse.
D) Impulse and final momentum.
Correct Answer: B
The provided content states that the impulse-momentum theorem relates the impulse delivered to an object and the object's change in momentum, as shown by the equation J = Δp.
A) the impulse delivered to the system.
B) the change in the system's momentum.
C) the rate of change of the system's momentum.
D) the integral of the system's momentum over time.
Correct Answer: C
Content point 3 explicitly states that the rate of change of a system's momentum is equal to the net external force exerted on that system, corresponding to the equation F_net = dp/dt.
A) J = p_f
B) J = p_i
C) J = p_f - p_i
D) J = p_f + p_i
Correct Answer: C
The impulse-momentum theorem is J = Δp. The change in any quantity (Δ) is the final value minus the initial value. Therefore, Δp = p_f - p_i, which means J = p_f - p_i.
A) The average net force on the object.
B) The final momentum of the object.
C) The acceleration of the object.
D) The change in momentum of the object.
Correct Answer: D
The definition of impulse is the integral of net force over time, J = ∫F_net(t)dt, which is the area under a Force vs. Time graph. The impulse-momentum theorem states that J = Δp. Therefore, the area under the curve is equal to the change in momentum.
A) The momentum must be zero.
B) The momentum must be constant.
C) The momentum must be changing at a constant rate.
D) The momentum must be increasing.
Correct Answer: B
From the equation F_net = dp/dt, if F_net is zero, then dp/dt must be zero. This means that the momentum p is not changing with time; it is constant. Consequently, the change in momentum Δp is also zero.
A) J = Δp
B) F_net = dp/dt
C) J = ∫F_net(t)dt
D) p = mv
Correct Answer: C
Content point 4 explicitly defines impulse as the integral of a force exerted on an object or system over a time interval, with the relevant equation J = ∫F_net(t)dt.
A) F_A = 2 * F_B
B) F_A = 0.5 * F_B
C) F_A = F_B
D) F_A = 4 * F_B
Correct Answer: A
Impulse J is related to average force F_avg and time Δt by J = F_avg * Δt. Since the impulse (J) is the same for both objects, F_A * Δt_A = F_B * Δt_B. Plugging in the times, F_A * (2s) = F_B * (4s). Solving for F_A gives F_A = (4/2) * F_B, or F_A = 2 * F_B.
A) The law of conservation of energy.
B) The definition of acceleration.
C) The impulse-momentum theorem.
D) Newton's Third Law.
Correct Answer: C
Rearranging gives dp = F_net * dt. Integrating both sides from the initial state to the final state gives ∫dp = ∫F_net * dt. This evaluates to Δp = J, which is the impulse-momentum theorem.
A) The impulse on the object at that time.
B) The net external force on the object at that time.
C) The change in momentum of the object.
D) The object's velocity at that time.
Correct Answer: B
The relationship F_net = dp/dt states that the net force is the time derivative (rate of change) of momentum. In a graph of momentum (p) versus time (t), the derivative dp/dt is represented by the slope of the tangent line. Therefore, the slope is the net external force.
A) J = F_net / Δt
B) J = F_net * Δt
C) J = Δp / Δt
D) J = F_net
Correct Answer: B
When the net force is constant, it can be taken out of the integral. The integral of dt from t1 to t2 is simply the time interval Δt. Therefore, the equation simplifies to J = F_net * Δt.
A) They are always in opposite directions.
B) They are always perpendicular to each other.
C) They are always in the same direction.
D) Their directions are unrelated.
Correct Answer: C
The equation J = Δp is a vector equation. For two vectors to be equal, both their magnitudes and their directions must be identical. Therefore, the direction of the impulse vector must be the same as the direction of the change in momentum vector.
A) multiply the maximum force by the total time.
B) differentiate the force function with respect to time.
C) integrate the net force function over the relevant time interval.
D) find the average of the initial and final forces.
Correct Answer: C
The impulse-momentum theorem states J = Δp. The definition of impulse for a time-varying force is J = ∫F_net(t)dt. Therefore, to find the change in momentum (Δp), one must calculate the impulse by integrating the net force over the time interval.
A) The impulse is the integral of the net force with respect to time, and the net force is the derivative of momentum with respect to time, making them inverse operations.
B) Both impulse and net force are vector quantities that cause a change in an object's velocity.
C) The impulse-momentum theorem (J=Δp) is only valid when the net force is constant, which is a special case of Newton's Second Law.
D) Net force is defined as the change in momentum, while impulse is defined as the change in force.
Correct Answer: A
The core connection is mathematical. F_net = dp/dt shows force as the time-derivative of momentum. J = ∫F_net(t)dt shows impulse as the time-integral of force. Integration and differentiation are inverse operations. Integrating F_net = dp/dt over time directly yields the impulse-momentum theorem, Δp = J, linking all the concepts.