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AP Physics C: Mechanics Practice Quiz: Conservation of Linear Momentum

Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026

Test your understanding with short quizzes. This quiz has 14 questions to check your progress.

Question 1 of 14

According to the principle of conservation of linear momentum, what happens to the total momentum of a system if the net external force on it is zero?

All Questions (14)

According to the principle of conservation of linear momentum, what happens to the total momentum of a system if the net external force on it is zero?

A) It is constant.

B) It increases at a constant rate.

C) It decreases to zero.

D) It is always zero.

Correct Answer: A

Based on the provided content: 'If the net external force on the selected system is zero, the total momentum of the system is constant.'

A student is analyzing a collision between two billiard balls on a frictionless table. To correctly apply the principle of conservation of linear momentum to the interaction, how should the student define the system?

A) Only the first ball.

B) Only the second ball.

C) Both billiard balls together.

D) The table on which the balls are rolling.

Correct Answer: C

The selection of a system determines whether its momentum changes. By defining the system as both balls, the forces they exert on each other during the collision are internal. With no net external forces (like friction), the total momentum of the two-ball system is conserved.

A system consists of two objects. Object 1 has a momentum of +10 kg·m/s and Object 2 has a momentum of -6 kg·m/s. If the total mass of the system is 8 kg, what is the velocity of the system's center of mass?

A) 0.5 m/s

B) 2.0 m/s

C) 4.0 m/s

D) 16.0 m/s

Correct Answer: A

The velocity of the center of mass is calculated using the equation $\vec{v}_{cm}=\frac{\sum\vec{p}_{i}}{\sum m_{i}}$. The sum of the momenta is $\sum\vec{p}_{i} = (+10 \text{ kg·m/s}) + (-6 \text{ kg·m/s}) = 4 \text{ kg·m/s}$. The total mass is $\sum m_{i} = 8 \text{ kg}$. Therefore, $\vec{v}_{cm} = \frac{4 \text{ kg·m/s}}{8 \text{ kg}} = 0.5 \text{ m/s}$.

A stationary firecracker on a frictionless surface explodes into two pieces. Within the system of the two pieces, what must be true about the momentum of each piece immediately after the explosion?

A) The momentum of each piece is zero.

B) The pieces have momenta that are equal in magnitude and direction.

C) The pieces have momenta that are equal in magnitude but opposite in direction.

D) The momentum of the larger piece is greater than the momentum of the smaller piece.

Correct Answer: C

The initial momentum of the system was zero. Since the explosion is an internal event with no net external forces, any change to the momentum of one piece must be balanced by an equivalent and opposite change of momentum in the other piece to keep the total momentum of the system constant at zero.

Which of the following statements best describes why internal forces within a system do not change the total linear momentum of the system?

A) Internal forces are always weaker than external forces.

B) For every internal force, there is an equal and opposite internal force, and their effects on the system's total momentum cancel out.

C) Internal forces only change the kinetic energy, not the momentum.

D) The system's mass must remain constant for internal forces to have no effect.

Correct Answer: B

This is a direct application of the principle that 'any change to the momentum of an object within a system must be balanced by an equivalent and opposite change of momentum elsewhere within the system.' These balanced changes are caused by Newton's Third Law pairs of internal forces.

If the total momentum of a collection of objects is zero, what can be concluded about the velocity of the system's center of mass?

A) The velocity of the center of mass is zero.

B) The velocity of the center of mass is constant but non-zero.

C) The velocity of the center of mass is increasing.

D) The velocity of the center of mass cannot be determined.

Correct Answer: A

The equation $\vec{v}_{cm}=\frac{\sum\vec{p}_{i}}{\sum m_{i}}$ relates the center of mass velocity to the total momentum ($\sum\vec{p}_{i}$). If the total momentum is zero, and the total mass is non-zero, the velocity of the center of mass must also be zero.

A person stands on a frictionless skateboard at rest. The person then throws a heavy ball forward. Which of the following describes the motion of the person-and-skateboard part of the system?

A) They move forward with the ball.

B) They remain at rest.

C) They move backward with a momentum equal in magnitude to the ball's momentum.

D) They move backward with a velocity equal in magnitude to the ball's velocity.

Correct Answer: C

The system is the person, skateboard, and ball. Initially, the total momentum is zero. Since throwing the ball is an internal action and there are no net external forces (frictionless), the total momentum must remain zero. The forward momentum of the ball must be balanced by an equivalent and opposite momentum of the person and skateboard.

A rocket in deep space, far from any significant gravitational forces, expels hot gas from its engine. If the system is defined as the rocket ONLY, is the momentum of this system conserved?

A) Yes, because the rocket's mass is decreasing.

B) Yes, because the engine provides an internal force.

C) No, because the expelled gas exerts a net external force on the rocket.

D) No, because the rocket is accelerating, which is impossible in a closed system.

Correct Answer: C

The selection of the system is critical. If the system is only the rocket, the force exerted by the expelled gas is an external force. This net external force changes the rocket's momentum. If the system were defined as the rocket *and* the expelled gas, the total momentum would be conserved.

For an isolated system (one with zero net external force), which statement about its center of mass is always true?

A) The center of mass must be at the origin.

B) The center of mass must be at rest.

C) The velocity of the center of mass is constant.

D) The center of mass accelerates.

Correct Answer: C

If the net external force on a system is zero, its total momentum is constant. According to the equation $\vec{v}_{cm}=\frac{\sum\vec{p}_{i}}{\sum m_{i}}$, if the total momentum ($\sum\vec{p}_{i}$) and total mass ($\sum m_{i}$) are constant, the velocity of the center of mass ($\vec{v}_{cm}$) must also be constant.

The primary condition required for the total linear momentum of a system to be conserved is that...

A) the system must be at rest.

B) the net external force on the system is zero.

C) all collisions within the system are perfectly elastic.

D) the total mass of the system remains constant.

Correct Answer: B

The provided content explicitly states, 'If the net external force on the selected system is zero, the total momentum of the system is constant.' This is the fundamental condition for conservation of linear momentum.

A cart is moving on a track. A student pushes on the cart in the direction of motion for a short time. If the system is defined as the cart, why is its linear momentum NOT conserved during the push?

A) The push is an internal force.

B) The cart's mass changes.

C) The student's push is a net external force on the system.

D) The momentum was conserved, but the kinetic energy was not.

Correct Answer: C

The system is defined as only the cart. The push from the student is a force originating from outside the system, making it a net external force. The presence of a net external force means the system's momentum will change.

A system has a total mass of 20 kg and its center of mass is moving at a constant velocity of 5 m/s to the right. What is the total linear momentum of the system?

A) 4 kg·m/s to the right.

B) 25 kg·m/s to the right.

C) 100 kg·m/s to the right.

D) Cannot be determined without knowing the individual masses.

Correct Answer: C

The equation for the center of mass velocity, $\vec{v}_{cm}=\frac{\sum\vec{p}_{i}}{\sum m_{i}}$, can be rearranged to find the total momentum, $\sum\vec{p}_{i} = (\sum m_{i}) \vec{v}_{cm}$. The total momentum is (20 kg) * (5 m/s) = 100 kg·m/s to the right.

An object at rest breaks into two pieces, A and B, which move apart. Within the system consisting of both pieces A and B, any change in the momentum of piece A...

A) must be greater than the change in momentum of piece B.

B) has no relation to the change in momentum of piece B.

C) must be balanced by an equivalent and opposite change in the momentum of piece B.

D) causes the velocity of the center of mass to increase.

Correct Answer: C

This directly follows the principle that 'In the absence of net external forces, any change to the momentum of an object within a system must be balanced by an equivalent and opposite change of momentum elsewhere within the system.' The explosion is an internal event.

Two asteroids are drifting in deep space and collide with each other. If the system is defined as the two asteroids together, which of the following quantities remains constant throughout the collision?

A) The velocity of each asteroid.

B) The total kinetic energy of the system.

C) The velocity of the system's center of mass.

D) The force exerted on each asteroid.

Correct Answer: C

In deep space, the net external force on the two-asteroid system is effectively zero. Therefore, the total momentum of the system is constant. Since $\vec{v}_{cm}=\frac{\sum\vec{p}_{i}}{\sum m_{i}}$, and both the total momentum and total mass are constant, the velocity of the center of mass must also remain constant.