AP Physics C: Mechanics Flashcards: Rolling
Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026
Review key ideas with interactive flashcards. This set includes 10 cards to help you master important concepts.
How is the total kinetic energy of an object that is both translating and rotating calculated?
The total kinetic energy is the sum of the system’s translational kinetic energy and its rotational kinetic energy.
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How is the total kinetic energy of an object that is both translating and rotating calculated?
The total kinetic energy is the sum of the system’s translational kinetic energy and its rotational kinetic energy.
Why does a rolling object have more kinetic energy than a non-rotating object of the same mass moving at the same translational speed?
A rolling object possesses both translational and rotational kinetic energy, while a non-rotating (sliding) object only has translational kinetic energy.
For an object rolling without slipping, what equation connects the center of mass acceleration ($a_{cm}$) to its angular acceleration ($\alpha$)?
The center of mass acceleration is related to the angular acceleration by the equation $a_{cm}=r\alpha$.
What does it mean for an object to be "rolling without slipping"?
Rolling without slipping means the translational motion of the object's center of mass is directly related to its rotational motion, such that the point of contact with the surface is momentarily at rest.
What two distinct types of motion are combined to describe the overall motion of a rolling object?
The motion of a rolling object is a combination of the translational motion of its center of mass and the rotational motion about its center of mass.
What is the equation for the total kinetic energy ($K_{tot}$) of a rolling object?
The equation for total kinetic energy is $K_{tot}=K_{trans}+K_{rot}$.
For an object rolling without slipping, how is the displacement of the center of mass ($\Delta x_{cm}$) related to its angular displacement ($\Delta heta$)?
The relationship is given by the equation $\Delta x_{cm}=r\Delta heta$, where r is the radius.
In an ideal case of rolling without slipping, what is the role of the frictional force regarding energy?
In ideal cases, the frictional force for an object rolling without slipping does not dissipate any energy from the system.
For an object rolling without slipping, what equation relates the center of mass velocity ($v_{cm}$) to its angular velocity ($\omega$)?
The relationship is given by the equation $v_{cm}=r\omega$, where r is the radius of the object.
A ball with a radius of 0.1 m rolls without slipping. If its center of mass accelerates at 2 m/s², what is its angular acceleration ($\alpha$)?
Using the equation $a_{cm}=r\alpha$, the angular acceleration is $\alpha = a_{cm}/r = (2 ext{ m/s²}) / (0.1 ext{ m}) = 20 ext{ rad/s²}$.