AP PreCalculus Practice Quiz: Polynomial Functions and Complex Zeros
Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026
Test your understanding with short quizzes. This quiz has 16 questions to check your progress.
Question 1 of 16
All Questions (16)
A) At most 7
B) Exactly 7
C) At least 7
D) It cannot be determined from the degree
Correct Answer: B
Based on the provided content, a polynomial function of degree n has exactly n complex zeros when counting multiplicities. Since the degree is 7, there must be exactly 7 complex zeros.
A) -3 + 2i
B) -3 - 2i
C) 3 - 2i
D) 2 + 3i
Correct Answer: C
The content states that if a+bi is a non-real zero of a polynomial function, then its conjugate, a-bi, is also a zero. The conjugate of 3 + 2i is 3 - 2i.
A) f(-x) = f(x)
B) f(-x) = -f(x)
C) f(x) = |f(x)|
D) f(x) = f(x+1)
Correct Answer: B
The provided content explicitly states that an odd function analytically has the property f(-x) = -f(x).
A) The multiplicity is odd.
B) The multiplicity is even.
C) The multiplicity is 1.
D) The multiplicity is non-real.
Correct Answer: B
The content states that if a real zero has even multiplicity, the signs of the output values are the same for input values near that zero. This corresponds to the graph touching the x-axis at the zero without crossing it. Therefore, the multiplicity must be even.
A) 2
B) 3
C) 4
D) 5
Correct Answer: B
The zeros can be found by setting each factor to zero. From (x-4)^3 = 0, we get the real zero x = 4. From x^2 + 9 = 0, we get x^2 = -9, which gives the non-real zeros x = 3i and x = -3i. Therefore, there are three distinct complex zeros: 4, 3i, and -3i.
A) 3
B) 4
C) 5
D) 6
Correct Answer: C
Since the polynomial has real coefficients, non-real zeros must come in conjugate pairs. The zero 2i implies its conjugate, -2i, is also a zero. The zero 1-i implies its conjugate, 1+i, is also a zero. The real zero is x=5. This gives a minimum of 5 zeros: 5, 2i, -2i, 1-i, and 1+i. A polynomial with 5 zeros must have a degree of at least 5.
A) p(c) = 0
B) p(0) = c
C) c must be a real number
D) The degree of p(x) is c
Correct Answer: A
The definition provided states that if a complex number 'a' is a zero of the polynomial function p, or a root of p(x) = 0, then p(a) = 0. Therefore, if c is a root, p(c) = 0.
A) Symmetry about the y-axis
B) Symmetry about the x-axis
C) Symmetry about the point (0,0)
D) Symmetry about the line y = x
Correct Answer: C
The content specifies that an odd function is graphically symmetric about the point (0,0), which is also known as symmetry with respect to the origin.
A) The zero at x = 3 has odd multiplicity.
B) The zero at x = 3 has even multiplicity.
C) The zero at x = 3 is a non-real zero.
D) The polynomial is an even function.
Correct Answer: B
The content states that if a real zero 'a' has even multiplicity, then the signs of the output values are the same for input values near x = a. Since the output values are positive on both sides of x = 3, the multiplicity of this zero must be even.
A) -4i
B) -4i and another real zero
C) 4i (multiplicity 2) and -4i
D) 2 and -4i
Correct Answer: B
A fifth-degree polynomial must have 5 complex zeros. We are given x = -2 with multiplicity 2, which accounts for two zeros. We are given the non-real zero x = 4i. Because the coefficients are real, its conjugate, x = -4i, must also be a zero. This accounts for a total of 2 + 1 + 1 = 4 zeros. Since the degree is 5, there must be one more zero. This fifth zero must be real, because if it were non-real, its conjugate would also have to be a zero, making a total of 6 zeros, which is impossible for a degree 5 polynomial.
A) f(x) = x^3 + x
B) f(x) = x^4 + 2x^2 + 5
C) f(x) = x^5 - 3x^3 + x - 1
D) f(x) = x^2 + x
Correct Answer: B
An even function has the property f(-x) = f(x). A polynomial function is even if all of its terms have even-powered variables (including the constant term, which can be written as 5x^0). In option B, f(-x) = (-x)^4 + 2(-x)^2 + 5 = x^4 + 2x^2 + 5 = f(x). The other options contain odd-powered terms, which prevent them from being even functions.
A) 2
B) 3
C) 4
D) 12
Correct Answer: B
The content states that the degree of a polynomial can be found by examining successive differences. If the nth differences are the first set of constant differences, then the degree of the polynomial is n. Since the third differences are constant, the degree of the polynomial is 3.
A) (-3, -5)
B) (3, 5)
C) (-3, 5)
D) (-5, 3)
Correct Answer: C
An odd function has the property f(-x) = -f(x). If the point (3, -5) is on the graph, it means f(3) = -5. Using the property, f(-3) = -f(3) = -(-5) = 5. Therefore, the point (-3, 5) must also be on the graph.
A) Exactly 4 real zeros.
B) Exactly 4 non-real zeros.
C) Exactly 4 complex zeros, which may be real or non-real.
D) At most 4 complex zeros.
Correct Answer: C
A polynomial function of degree n has exactly n complex zeros. Real numbers are a subset of complex numbers (e.g., 5 can be written as 5+0i). Therefore, a degree 4 polynomial has exactly 4 complex zeros, but these zeros can be a combination of real and non-real numbers.
A) 2
B) 3
C) 4
D) 5
Correct Answer: B
We must find the successive differences. First differences: (3-2)=1, (10-3)=7, (29-10)=19, (66-29)=37. Second differences: (7-1)=6, (19-7)=12, (37-19)=18. Third differences: (12-6)=6, (18-12)=6. Since the third differences are constant, the degree of the polynomial is 3.
A) The polynomial must have an odd degree.
B) The value p(a-bi) must equal 0.
C) The value p(a) must be 0.
D) The polynomial cannot have any real zeros.
Correct Answer: B
The content provides two key rules. First, if a+bi is a zero, then p(a+bi) = 0. Second, if a+bi is a non-real zero of a polynomial with real coefficients, its conjugate a-bi is also a zero. If a-bi is a zero, then by definition, p(a-bi) must equal 0.