AP PreCalculus Practice Quiz: Inverses of Exponential Functions
Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026
Test your understanding with short quizzes. This quiz has 12 questions to check your progress.
Question 1 of 12
All Questions (12)
A) f(x) = x^{b}
B) f(x) = log_{b}x
C) f(x) = -b^{x}
D) f(x) = b^{-x}
Correct Answer: B
Content point 4 explicitly states that f(x) = log_{b}x and g(x) = b^{x} are inverse functions.
A) The x-axis
B) The y-axis
C) The line y = -x
D) The line y = x
Correct Answer: D
Content point 5 states that the graph of a logarithmic function is a reflection of its inverse exponential function over the graph of the identity function, h(x) = x.
A) (3, 27)
B) (-3, 1/27)
C) (27, 3)
D) (1/3, 27)
Correct Answer: C
Based on content point 6, if (s, t) is an ordered pair of an exponential function, then (t, s) is an ordered pair of its inverse logarithmic function. Therefore, (3, 27) on the exponential function corresponds to (27, 3) on the logarithmic function.
A) Output values change additively as input values also change additively.
B) Output values change multiplicatively as input values change additively.
C) Output values change multiplicatively as input values also change multiplicatively.
D) Output values change additively as input values change multiplicatively.
Correct Answer: D
This is the definition provided in content point 3: Logarithmic growth is characterized by output values changing additively as input values change multiplicatively.
A) b > 0 and b ≠ 1
B) b < 0
C) b = 1
D) b can be any real number except 0
Correct Answer: A
Content point 2 specifies the general form of a logarithmic function and states that the base b must satisfy the conditions b > 0 and b ≠ 1.
A) y = log_{x}5
B) x = log_{y}5
C) y = log_{5}x
D) y = x^{5}
Correct Answer: C
Following content point 1, we construct the inverse. We start with y = 5^{x}. To find the inverse, we swap x and y to get x = 5^{y}. Then, we solve for y by converting to logarithmic form, which is y = log_{5}x. This matches the rule from content point 4.
A) It is a reflection of g(x) over the y-axis and contains the point (-m, n).
B) It is a reflection of g(x) over the line y = x and contains the point (n, m).
C) It is a reflection of g(x) over the x-axis and contains the point (m, -n).
D) It is a reflection of g(x) over the line y = x and contains the point (m, n).
Correct Answer: B
This question combines two concepts. Content point 5 states that the graphs are reflections over y = x. Content point 6 states that if (s, t) is on the exponential function, (t, s) is on the logarithmic function. Therefore, the inverse graph is a reflection over y = x and contains the point (n, m).
A) 8
B) 9
C) 11
D) 14
Correct Answer: B
According to content point 3, for logarithmic growth, output values change additively as input values change multiplicatively. The input changes from 3 to 9 by a factor of 3 (9/3 = 3), and the output changes from 5 to 7 by adding 2 (7-5 = 2). To get the next value, we multiply the input by 3 again (9 * 3 = 27), so we must add 2 to the output: 7 + 2 = 9.
A) (16, 4), demonstrating a reflection over the line y = x.
B) (4, 16), demonstrating that the functions are identical.
C) (-4, 1/16), demonstrating a reflection over the y-axis.
D) (16, 4), demonstrating a reflection over the x-axis.
Correct Answer: A
This question synthesizes content points 5 and 6. From point 6, if (4, 16) is on g(x), then (16, 4) is on its inverse f(x). From point 5, this swapping of coordinates is the algebraic result of the geometric reflection of the graph over the line y = x.
A) (k, j)
B) (-k, j)
C) (k, -j)
D) (j, k)
Correct Answer: D
This question combines several concepts. An exponential function with an initial value of 1 is g(x) = b^x (Content 1). Its reflection over the identity function h(x)=x is its inverse, the logarithmic function f(x) = log_b(x) (Content 5). If (k, j) is an ordered pair of the exponential function, then (j, k) is the corresponding ordered pair on its inverse (Content 6).
A) f(x) = 8 log_{3}x
B) f(x) = 3 log_{8}x
C) f(x) = log_{3}(x) + 8
D) f(x) = log_{8}(x) + 3
Correct Answer: B
This is a direct application of content point 3. The input changes multiplicatively (by 8), and the output changes additively (by 3). This implies a logarithmic function with base 8, so it has the form f(x) = a log_{8}x. To find 'a', consider two points x_1 and x_2=8x_1. The change in output is f(x_2) - f(x_1) = a log_{8}(8x_1) - a log_{8}(x_1) = a(log_{8}(8) + log_{8}(x_1)) - a log_{8}(x_1) = a*log_{8}(8) = a*1 = a. Since the output increases by 3, a = 3. The function is f(x) = 3 log_{8}x.
A) log_5(3) = 125
B) log_3(5) = 125
C) log_5(125) = 3
D) log_125(5) = 3
Correct Answer: C
The exponential statement 5^3 = 125 means the ordered pair (s, t) = (3, 125) is on the function g(x)=5^x. According to content point 6, the corresponding ordered pair on the inverse logarithmic function is (t, s) = (125, 3). This means f(125) = 3, which is written as log_5(125) = 3.