AP PreCalculus Practice Quiz: Matrices Modeling Contexts
Written by AP Content Team, Verified for 2026 AP Exams, Last updated: May 2026
Test your understanding with short quizzes. This quiz has 15 questions to check your progress.
Question 1 of 15
All Questions (15)
A) [[0.90, 0.05], [0.10, 0.95]]
B) [[0.10, 0.05], [0.90, 0.95]]
C) [[0.90, 0.10], [0.05, 0.95]]
D) [[1.10, 1.05], [0.90, 0.95]]
Correct Answer: A
This question requires constructing a model of a scenario involving transitions between two states. The first column represents people starting in the City Center: 90% stay (0.90) and 10% move to the suburbs (0.10). The second column represents people starting in the Suburbs: 5% move to the City Center (0.05) and 95% stay (0.95). The resulting matrix is [[0.90, 0.05], [0.10, 0.95]].
A) [1400; 1600]
B) [800; 1400]
C) [2400; 1800]
D) [1100; 1900]
Correct Answer: A
To predict the future state, we find the product of the transition matrix T and the initial state vector S_0. S_1 = T * S_0 = [[0.8, 0.3], [0.2, 0.7]] * [1000; 2000] = [(0.8*1000 + 0.3*2000); (0.2*1000 + 0.7*2000)] = [800 + 600; 200 + 1400] = [1400; 1600].
A) The initial distribution between states.
B) The predicted state after one transition step.
C) The long-term steady state of the system.
D) The state of the system in the past.
Correct Answer: B
As stated in the content, the product of a matrix that models transitions between states and a corresponding state vector can be used to predict future states. Specifically, this product gives the state after one transition.
A) [0.81; 0.19]
B) [0.85; 0.15]
C) [0.9; 0.1]
D) [0.78; 0.22]
Correct Answer: B
To predict the state for n=2 transition steps, we can calculate S_2 = T * S_1, where S_1 = T * S_0. First, S_1 = [[0.9, 0.4], [0.1, 0.6]] * [1; 0] = [0.9; 0.1]. Then, S_2 = [[0.9, 0.4], [0.1, 0.6]] * [0.9; 0.1] = [(0.9*0.9 + 0.4*0.1); (0.1*0.9 + 0.6*0.1)] = [0.81 + 0.04; 0.09 + 0.06] = [0.85; 0.15].
A) [480; 520]
B) [360; 640]
C) [500; 500]
D) [200; 800]
Correct Answer: C
To predict a past state, we use the product of the inverse of the transition matrix and the current state vector (S_0 = T⁻¹ * S_1). First, find T⁻¹: det(T) = (0.6)(0.8) - (0.2)(0.4) = 0.4. T⁻¹ = (1/0.4) * [[0.8, -0.2], [-0.4, 0.6]] = [[2, -0.5], [-1, 1.5]]. Then, S_0 = [[2, -0.5], [-1, 1.5]] * [400; 600] = [(2*400 - 0.5*600); (-1*400 + 1.5*600)] = [800 - 300; -400 + 900] = [500; 500].
A) An inverse state
B) An initial state
C) A transition state
D) A steady state
Correct Answer: D
The content states that repeated multiplication of a matrix that models the transitions between states and corresponding resultant state vectors can predict the steady state. A steady state is a condition where the state vector remains constant from one transition to the next.
A) Multiply T by S_k.
B) Multiply the inverse of T by S_k.
C) Multiply the transpose of T by S_k.
D) Multiply S_k by itself.
Correct Answer: B
According to the provided content, the product of the inverse of a matrix that models transitions between states and a corresponding state vector can predict past states. Therefore, to find S_(k-1), one must calculate T⁻¹ * S_k.
A) The number of square miles that changed from Residential to Commercial.
B) The total number of square miles of Residential land after one more decade.
C) The total number of square miles of Commercial land after one more decade.
D) The initial amount of Residential land two decades ago.
Correct Answer: B
The product of the transition matrix and a state vector predicts the next state. Since the state vector is defined as S = [Residential; Commercial], the top number in the resulting vector S_2 represents the predicted amount of Residential land at that future time.
A) 15
B) 1.15
C) 0.15
D) -0.15
Correct Answer: C
The content specifies that a contextual scenario can indicate the rate of transitions between states as percent changes. A 15% change is represented as the decimal 0.15 in the matrix.
A) n * T * S_0
B) T * (S_0)^n
C) (T⁻¹)^n * S_0
D) T^n * S_0
Correct Answer: D
To apply matrix models to predict future states for n transition steps, the transition matrix T is raised to the power of n and then multiplied by the initial state vector S_0. This is equivalent to repeatedly multiplying by T, n times.
A) [400; 600]
B) [440; 560]
C) [500; 500]
D) [600; 400]
Correct Answer: C
To find a past state, we use the inverse matrix. To go back two steps, we apply the inverse twice: S_0 = T⁻¹ * (T⁻¹ * S_2). First, T⁻¹ = [[2, -0.5], [-1, 1.5]]. Then, S_1 = T⁻¹ * S_2 = [[2, -0.5], [-1, 1.5]] * [360; 640] = [720-320; -360+960] = [400; 600]. Finally, S_0 = T⁻¹ * S_1 = [[2, -0.5], [-1, 1.5]] * [400; 600] = [800-300; -400+900] = [500; 500].
A) [[0.95, 0.05], [0.60, 0.40]]
B) [[0.95, 0.40], [0.05, 0.60]]
C) [[0.95, 0.60], [0.05, 0.40]]
D) [[0.05, 0.60], [0.95, 0.40]]
Correct Answer: C
This requires constructing a model. The first column represents the 'Working' state: 95% stay Working (0.95), so 5% become Broken (0.05). The second column represents the 'Broken' state: 60% become Working (0.60), so 40% stay Broken (0.40). The matrix is [[0.95, 0.60], [0.05, 0.40]].
A) [500; 500]
B) [700; 300]
C) [100; 900]
D) [250; 750]
Correct Answer: D
A steady-state vector S satisfies the equation T*S = S. We can test the options. For S = [250; 750]: T*S = [[0.7, 0.1], [0.3, 0.9]] * [250; 750] = [(0.7*250 + 0.1*750); (0.3*250 + 0.9*750)] = [175 + 75; 75 + 675] = [250; 750]. Since T*S = S, this is the steady-state vector.
A) [200; 800]
B) [310; 690]
C) [286; 714]
D) [357; 643]
Correct Answer: C
To find the past state, we calculate S_(k-1) = T⁻¹ * S_k. First, find T⁻¹: det(T) = (0.8)(0.9) - (0.1)(0.2) = 0.72 - 0.02 = 0.7. T⁻¹ = (1/0.7) * [[0.9, -0.1], [-0.2, 0.8]]. Then, S_(k-1) = (1/0.7) * [[0.9, -0.1], [-0.2, 0.8]] * [300; 700] = (1/0.7) * [270 - 70; -60 + 560] = (1/0.7) * [200; 500] = [2000/7; 5000/7] ≈ [286; 714].
A) [1; 0]
B) [0.2; 0.8]
C) [0.9; 0.1]
D) [0.8; 0.2]
Correct Answer: B
To predict the next state, we multiply the transition matrix by the current state vector: S_1 = T * S_0. S_1 = [[0.2, 0.9], [0.8, 0.1]] * [1; 0] = [(0.2*1 + 0.9*0); (0.8*1 + 0.1*0)] = [0.2; 0.8]. This represents a 20% chance of remaining in the 'Charging' state and an 80% chance of transitioning to 'Not Charging'.